6x^2+17x-143=0

Solution for 6x^2+17x-143=0 equation:

6x^2+17x-143=0

a = 6; b = 17; c = -143;
Δ = b2-4ac
Δ = 172-4·6·(-143)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-61}{2*6}=\frac{-78}{12}
=-6+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+61}{2*6}=\frac{44}{12}
=3+2/3
$